210. Course Schedule II
Basically same as 207
class Solution:
def findOrder(self, numCourses: int, prerequisites: List[List[int]]) -> List[int]:
indeg = [0] * numCourses
M = defaultdict(list)
for v1, v2 in prerequisites:
M[v2].append(v1)
indeg[v1] += 1
dq = deque([i for i in range(len(indeg)) if indeg[i] == 0])
res = []
while dq:
course = dq.popleft()
res.append(course)
for vv in M[course]:
indeg[vv] -= 1
if indeg[vv] == 0:
dq.append(vv)
return [] if len(res) != numCourses else res